Chemistry Help, Please! A researcher....?

Well, you start out with an alkene and react it with HBr in the presence of dietyl ether. As long as you have your starting material drawn right, you are going to get the anti-markovnicov reaction in which the double bond opens up and grabs the H of the HBr. You are then left with a carbocation. But before the Br can come onto the cation, if you look closely, a hydride shift can be performed to a make a more stable carbocation. Then the Br can come on. You should get 1-bromo-1-methyl-butane. If you draw out the molecule you can see for a proton NMR you would get 6 singlets, 2 qaurtets , and 3 triplets.