Organic chemistry sodium borohydride reduction question?

I'm pretty sure the answer is that compound F is 2-acetylfluorene. I figured it out by finding the molecular formula using the combustion data. Its C15H12O. The second guy was wrong because he used the incorrect ratio of (12/32) for mass of carbon. If you use the correct ratio of (12/44) you will get 1.7g of carbon which translates to 0.1440 moles. See the second source link for specific details of how to do combustion calculations.